Two bodies of masses $2 k g$ & $1.8 k g$ are separated by $20 m$ .
The force between them becomes $4$ times at a distance of :

5 m

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10 m

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20 m

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None of them

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Solution

The correct option is C $10 m$
The gravitational force between two masses is inversely proportional to the square of the distance between two masses.
$\frac{F_{1}}{F_{2}} = {(\frac{r_{2}}{r_{1}})}^{2}$
$\frac{1}{4} = {(\frac{r_{2}}{20})}^{2}$

$r_{2} = 10 m$

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Two bodies of masses 2kg & 1.8kg are separated by 20m .The force between them becomes 4 times at a distance of :

The correct option is C 10mThe gravitational force between two masses is inversely proportional to the square of the distance between two masses.F1F2=(r2r1)214=(r220)2 r2=10m

Two bodies of masses $2 k g$ & $1.8 k g$ are separated by $20 m$ .
The force between them becomes $4$ times at a distance of :

The correct option is C $10 m$
The gravitational force between two masses is inversely proportional to the square of the distance between two masses.
$\frac{F_{1}}{F_{2}} = {(\frac{r_{2}}{r_{1}})}^{2}$
$\frac{1}{4} = {(\frac{r_{2}}{20})}^{2}$

$r_{2} = 10 m$