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Question

# Two bodies of masses m1 and m2 are initially at rest at an infinite distance apart. They are then allowed to move towards each other under mutual gravitational attraction. Their relative velocity of approach at a separation distance r between them is

A
[2G(m1m2)r]1/2
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B
[2Gr(m1+m2)]1/2
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C
[r2G(m1m2)]1/2
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D
[2Grm1m2]1/2
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Solution

## The correct option is B [2Gr(m1+m2)]1/2 (When allowed to move towards each other) Let velocities of these masses at r distance from each other be v1 and v2 respectively. By conservation of momentum m1v1−m2v2=0⇒m1v1=m2v2 ... (i) By conservation of energy Decrease in P.E.=Increase in K.E. Gm1m2r=12m1v21+12m2v22 ... (ii) On solving equation (i) and (ii) v1=√2Gm22r(m1+m2) and v2=√2Gm21r(m1+m2) ∴vapp=|v1|+|v2|=√2Gr(m1+m2)

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