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Newton's Laws for System of Particles

Two bodies of...

Question

Two bodies of masses $m_{1}$ and $m_{2}$ have equal kinetic energies. If $p_{1}$ and $p_{2}$ are their respective momentum, then ratio $p_{1} : p_{2}$ is equal to

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Solution

The correct option is C

$P = \sqrt{2 m E} (i f E = c o n s t .) ∴ \frac{P_{1}}{P_{2}} = \sqrt{\frac{m_{1}}{m_{2}}}$

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Two bodies of masses m1 and m2 have equal kinetic energies. If p1 and p2 are their respective momentum, then ratio p1:p2 is equal to

The correct option is C P=√2mE(ifE=const.)∴P1P2=√m1m2

Two bodies of masses $m_{1}$ and $m_{2}$ have equal kinetic energies. If $p_{1}$ and $p_{2}$ are their respective momentum, then ratio $p_{1} : p_{2}$ is equal to

The correct option is C

$P = \sqrt{2 m E} (i f E = c o n s t .) ∴ \frac{P_{1}}{P_{2}} = \sqrt{\frac{m_{1}}{m_{2}}}$