Two bodies of masses $m_{1}$ , $m_{2}$ and are connected by a light , in extensible which passes over a friction-less pulley. If the pulley is moving upward with uniform acceleration 0.5g , then the tension in the string is

\frac{3 m_{1} m_{2}}{m_{1} + m_{2}} g

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\frac{m_{1} + m_{2}}{4 m_{1} m_{2}} g

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\frac{m_{1} m_{2}}{m_{1} + m_{2}} g

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\frac{m_{1} - m_{2}}{m_{1} + m_{2}} g

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Solution

The correct option is A $\frac{3 m_{1} m_{2}}{m_{1} + m_{2}} g$
Applying pseudo force ;
$\begin{matrix} a_{net} & = \frac{F_{net}}{M_{total}} a & = \frac{3 / 2 (m_{1} - m_{2}) g}{m_{1} + m_{2}} \end{matrix}$
and
$m_{1} \Rightarrow \frac{3 m_{1} g - T}{2} \Rightarrow m_{1}$ a
$\frac{3}{2} m_{1} g - T = m_{1} 3 / 2 \frac{(m_{1} - m_{2})}{m_{1} + m_{2}} g$
$\begin{matrix} T = 3 / 2 \times 2 (\frac{m, m_{2}}{m_{1} + m_{2}}) g T = \frac{3 m_{1} m_{2}}{m_{1} + m_{2}} g \end{matrix}$

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Two bodies of masses m1, m2 and are connected by a light , in extensible which passes over a friction-less pulley. If the pulley is moving upward with uniform acceleration 0.5g , then the tension in the string is

The correct option is A 3m1m2m1+m2gApplying pseudo force ; anet =Fnet Mtotal a=3/2(m1−m2)gm1+m2 and m1⇒3m1g−T2⇒m1 a 32m1g−T=m13/2(m1−m2)m1+m2g T=3/2×2(m,m2m1+m2)gT=3m1m2m1+m2g

Two bodies of masses $m_{1}$ , $m_{2}$ and are connected by a light , in extensible which passes over a friction-less pulley. If the pulley is moving upward with uniform acceleration 0.5g , then the tension in the string is