Two bodies of masses m and 3m, moving with velocities 3v and v respectively along same direction, collide with each other. After collision they stick together and move with velocity V in the same direction. Then:

V = v

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V = \frac{3}{2} V

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V = 2 v

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V = \frac{4}{3} V

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Solution

The correct option is B $V = \frac{3}{2} V$
Given : $m_{1} = m$ $m_{2} = 3 m$ $u_{1} = 3 v$ $u_{2} = v$
From conservation of linear momentum, $P_{f} = P_{i}$
$m V + 3 m V = m (3 v) + 3 m (v)$
$⟹ V = \frac{3}{2} v$

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Two bodies of masses m and 3m, moving with velocities 3v and v respectively along same direction, collide with each other. After collision they stick together and move with velocity V in the same direction. Then:

The correct option is B V=32VGiven : m1=m m2=3m u1=3v u2=vFrom conservation of linear momentum, Pf=PimV+3mV=m(3v)+3m(v)⟹ V=32v

The correct option is B $V = \frac{3}{2} V$
Given : $m_{1} = m$ $m_{2} = 3 m$ $u_{1} = 3 v$ $u_{2} = v$
From conservation of linear momentum, $P_{f} = P_{i}$
$m V + 3 m V = m (3 v) + 3 m (v)$
$⟹ V = \frac{3}{2} v$