Two bodies of masses ′m′ and ′4m′ are having linear momentum in the ratio of 2:1, respectively. The ratio of their kinetic energy is
A
4:1
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B
1:4
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C
1:8
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D
16:1
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Solution
The correct option is D16:1 Lets assume that P1= Linear momentum of mass ′m′ KE1= Kinetic energy of mass ′m′ P2= Linear momentum of mass ′4m′ KE2= Kinetic energy of mass ′4m′
We also know that, the relation between kinetic energy and linear momentum is given by, KE=P22m KE1KE2=P212mP222×4m