Question

Two bodies of masses m and $4m$ are moving with equal kinetic energies. the ratio of their linear momenta?

Answer 1

Assuming kinetic energy to be same for both the body,

$\frac{1}{2}{m}_1{v}_1^2=\frac{1}{2}{m}_2{v}_2^2$

$\left(m_1{v}_1\right)\times v_1=\left(m_2{v}_2\right)\times v_2$

$\frac{m_1{v}_1}{m_2{v}_2}=\frac{v_2}{v_1}$

$\frac{P_1}{P_2}=\frac{v_1}{v_2}$