Two bodies of masses $m$ and $4 m$ are moving with equal kinetic energy. Then the ratio of their linear momentum will be

1 : 1

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2 : 1

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4 : 1

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1 : 2

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Solution

The correct option is B $1 : 2$
relation between Linear momentum and KE is $p = \sqrt{2 m K E}$
therefore for m and 4m masses we have
$p_{1} : p_{2} = \sqrt{m_{1}} : \sqrt{m_{2}} = \sqrt{m} : \sqrt{4 m} = 1 : 2$

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