CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

two bodies of masses M1 and M2 (M1 not equal to M2) moving with initial velocity u1 and u2 (u1>u2) along a straight line in the same direction, suffer perfect head on collision. Find their velocities after the collision

Open in App
Solution

Dear studentlet v1 the speed of m1 and v2be the speed of m2 after collisionlet all velocities, initial and final be rightwards.by conservation of momentumm1u1+m2u2=m1v1+m2v2.................(1)since thier is a perfectly elastic collisioncoefficient of restitution e = 1 = velocity of separationvelocity of approach1=v2-v1u1-u2.........................(2)on solving (1) and (2)v1=u1(m1-m2)+2m2u2(m1+m2)v1=u2(m2-m1)+2m1u1(m1+m2)Regards

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
A Sticky Situation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon