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Question

two bodies of masses M1 and M2 (M1 not equal to M2) moving with initial velocity u1 and u2 (u1>u2) along a straight line in the same direction, suffer perfect head on collision. Find their velocities after the collision

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Solution

Dear studentlet v1 the speed of m1 and v2be the speed of m2 after collisionlet all velocities, initial and final be rightwards.by conservation of momentumm1u1+m2u2=m1v1+m2v2.................(1)since thier is a perfectly elastic collisioncoefficient of restitution e = 1 = velocity of separationvelocity of approach1=v2-v1u1-u2.........................(2)on solving (1) and (2)v1=u1(m1-m2)+2m2u2(m1+m2)v1=u2(m2-m1)+2m1u1(m1+m2)Regards

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