Two bodies of the same volume but of different masses are in equilibrium be violated if the lever is immersed in water so that the bodies are completely submerged?

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Solution

The equilibrium condition for the lever is the equality of the moments of forces of gravity $m_{1} g$ and $m_{2} g$ of the bodies. Since they are different, their arms $l_{1}$ and $l_{2}$ are also different since $m_{1} g l_{1} = m_{2} g l_{2}$ .
When the lever is immersed in water, the forces of gravity is supplemented by the buoyan of water, which is proportional to the volume of the body. By hypothesis, $F_{1} = F_{2}$ , and therefore $(m_{1} g - F_{1}) l_{1} \neq (m_{2} g - F_{2}) l_{2}$ .
Thus, the equilibrium of the lever will be violated.

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