You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Unit Vectors

Two bodies st...

Question

Two bodies starts moving from same point along a straight line with velocities $v_{1} = 6 m / s$ and $v_{2} = 10 m / s$ , simultaneously. After what time their separation becomes $40 m$ ?

6 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $10 s$
$A : v_{1} = 6 m / s$
$B : v_{2} = 10 m / s$
let $A$ and $B$ travel $s_{1} & s_{2}$ respectively
$s_{1} = v_{1} t$
$s_{2} = v_{2} t$
$s_{2} - s_{1} = (v_{2} - v_{1}) t$
$40 = (10 - 6) t$
$t = 10 s$

Suggest Corrections

Similar questions

Q. Two particles one with a constant velocity 50 m/s and another starts from rest with uniform acceleration

10 m / s^{2}

starts moving simultaneously from the same point and in the same direction at a distance 125 m. Calculate time.

Q. Two bodies

1

and

2

are projected simultaneously with velocities

V_{1} = 2 m/s

and

V_{2} = 4 m/s

. The body

1

is projected vertically up from the top of a cliff of height

h = 10 m

and the body

2

is projected vertically up from the bottom of the cliff . If the bodies meet, find the time in

(s)

of meeting of the bodies.

Q. Two elastic bodies P and Q having equal masses are moving along the same line with velocities of 16 m/s and 10m/s respectively. Their velocities after the elastic collision will be in m/s :

An object is moving in a straight-line path has a velocity of $40 m/s$ at some instant. After $10 s$ , its velocity changed to $80 m/s$ . What is the average acceleration of the ball during this time interval?

Q. Two cars 1 and 2 move with velocities

v_{1}

and

v_{2}

respectively, on a straight road in same direction. When the cars are separated by a distance d, the driver of car 1 applies brakes and the car moves with uniform retardation

a_{1}

. Simultaneously, car 2 starts accelerating with

a_{2}

. If

v_{1} {> v}_{2}

. Find the minimum initial separation between the cars to avoid collision between them.

Join BYJU'S Learning Program

Two bodies starts moving from same point along a straight line with velocities v1=6 m/s and v2=10 m/s, simultaneously. After what time their separation becomes 40 m?

The correct option is D 10 sA:v1=6m/sB:v2=10m/slet A and B travel s1 & s2 respectivelys1=v1ts2=v2ts2−s1=(v2−v1)t40=(10−6)tt=10 s

Two bodies starts moving from same point along a straight line with velocities $v_{1} = 6 m / s$ and $v_{2} = 10 m / s$ , simultaneously. After what time their separation becomes $40 m$ ?

The correct option is D $10 s$
$A : v_{1} = 6 m / s$
$B : v_{2} = 10 m / s$
let $A$ and $B$ travel $s_{1} & s_{2}$ respectively
$s_{1} = v_{1} t$
$s_{2} = v_{2} t$
$s_{2} - s_{1} = (v_{2} - v_{1}) t$
$40 = (10 - 6) t$
$t = 10 s$