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Standard XII

Physics

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Two bodies we...

Question

Two bodies were thrown simultaneously from the same point, one straight up, and the other, at an angle of $30^{o}$ to the horizontal. The initial speed of each body is $20$ $m s^{- 1} .$ Neglecting air resistance, the distance between the bodies at $t = 1.2$ later

20 m

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30 m

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24 m

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50 m

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Solution

The correct option is C $24 m$
For vertically projected body,
$y + 1 = u t - 0.5 g t^{2} = 16.8 m$
$x_{1} = 0$
For the projectile at 30 degrees,
$U_{x} = u c o s θ$
$U_{y} = u s i n θ$
$y_{2} = U_{y} t - 0.5 g t^{2} = 4.8 m$
$x_{2} = U_{x} t$

$R = \sqrt{(y_{1} - y_{2})^{2} + (x_{1} - x_{2})^{2}} = 24$

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Two bodies were thrown simultaneously from the same point, one straight up, and the other, at an angle of 30o to the horizontal. The initial speed of each body is 20 ms−1. Neglecting air resistance, the distance between the bodies at t=1.2 later

The correct option is C 24 mFor vertically projected body, y+1=ut−0.5gt2=16.8 mx1=0For the projectile at 30 degrees, Ux=ucosθUy=usinθy2=Uyt−0.5gt2=4.8 mx2=UxtR=√(y1−y2)2+(x1−x2)2=24

Two bodies were thrown simultaneously from the same point, one straight up, and the other, at an angle of $30^{o}$ to the horizontal. The initial speed of each body is $20$ $m s^{- 1} .$ Neglecting air resistance, the distance between the bodies at $t = 1.2$ later