Question

Two bottles of a and b contains 1M and 1m aqueous solution (d=1g/mL)of sulphuric acid which one is more concentrated.

Answer 1

To compare convert both in same unit of concentration (in molality).

{ solution=$H_{2}S{O}_4+H_{2}O$}

In A, 1M means that 1mol of $H_{2}S{O}_4$ is in 1000ml of solution.

So 1 mol $H_{2}S{O}_4$ is in 1000g of solution(as density is 1g/ml)

Now in 1000g of solution, mass of $H_{2}S{O}_4$=1 mol=98g

⇒1mol of $H_{2}S{O}_4$ is in (1000g-98g= 902g) of water.

Hence molality of $H_{2}S{O}_4$ in A=(1/902)*1000m=1.108m>molality in bottle B

So bottle A is more concentrated of $H_{2}S{O}_4$ as compared to bottle B.