Two boys exert forces of 40 N and 60 N in opposite directions on an object.
The resultant force is
(a) a force of 100 N acting in the direction of the larger force.
(b) a force of 100 N acting in the direction of the smaller force.
(c) a force of 20 N acting in the direction of the smaller force.
(d) a force of 20 N acting in the direction of the larger force.

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Solution

(d) a force of 20 N acting in the direction of the larger force

Let Force F_A be 40 N, and Force F_Bbe 60 N.
The forces are acting in opposite directions. So, the net force will act in the direction of larger force, i.e., Force, F_B.
Net force = F_B - F_A= 60 - 40
= 20 N
Therefore, the resultant force is a force of 20 N acting in the direction of the larger force.

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