Two boys start running together from the same place at the speed of $6$ km/hr and $4$ km/hr . Find the distance between them after $6$ minutes, if they run in the opposite directions.

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Solution

The correct option is C $1$ km
We know,

$d i s t a n c e = s p e e d \times t i m e$

When two objects are moving in opposite directions at $x k m / h r$ and $y k m / h r$ then their $r e l a t i v e s p e e d = (x + y) k m / h r$
Therefore, $r e l a t i v e s p e e d = 6 + 4 = 10 k m / h r$
$t i m e = 6 m i n u t e s$
$6 m i n u t e s = 6 \times \frac{1}{60} = \frac{1}{10} = 0.1 h r$

$d i s t a n c e = 10 \times 0.1 = 1 k m$

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Two boys start running together from the same place at the speed of 6 km/hr and 4 km/hr . Find the distance between them after 6 minutes, if they run in the opposite directions.

The correct option is C 1 kmWe know,distance=speed×timeWhen two objects are moving in opposite directions at x km/hr and y km/hr then their relative speed=(x+y) km/hrTherefore, relative speed=6+4=10 km/hrtime=6 minutes6 minutes=6×160=110=0.1 hrdistance=10×0.1=1 km

Two boys start running together from the same place at the speed of $6$ km/hr and $4$ km/hr . Find the distance between them after $6$ minutes, if they run in the opposite directions.