Question

Two brands of chocolates are available in packs of $24$ and $15$ respectively. If I need to buy an equal number of chocolates of both kinds, what is the least number of boxes of each kind I would need to buy?

• A. $2$ of first kind, $8$ of second kind
• B. $5$ of first kind, $8$ of second kind
• C. $5$ of first kind, $7$ of second kind
• D. $2$ of first kind, $7$ of second kind

Answer 1

Answer: (B)

$5$ of first kind, $8$ of second kind

Given, two brands of chocolates are available in pack of 24 and 15 respectively.

We need to buy an equal number of chocolates of both kinds.

$\text{For this we find the LCM of 24 and 15}$

Now,

$24=2^3\times 3$

$15=3\times 5$

$LCM(24,15)=2^3\times 3\times 5=120$

Now,

the number of boxes of pack of 24 $=\frac{120}{24}=5$

and the number of boxes of pack of 15 $=\frac{120}{15}=8$

$\text{option B is correct.}$