wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two buildings A and B are 20m apart. Building A has a window at a height of 50m above the ground and building B has a window at a height of 30.4m above the ground. With what speed must a man throw a ball horizontally from the window of building A so that it enters the window of building B?

A
5ms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10ms1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
15ms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
20ms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 10ms1

To make the ball enter the window time taken to cover the horizontal separation between the two buildings must be equal to the time taken for vertical fall

t=xu

t=2yg

Comparing the above two equations

2yg=xu

u=xg2y

=209.82×19.6

=10m/s


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Realistic Collisions
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon