Two bulbs A and B are marked as ‘A’ 60W, 220V & ‘B’ 100W, 220V are connected in parallel to 220 V source. Which of the two will glow brighter?
Bulb B
When voltage is constant then P = V2R
P ∝ 1R so, when resistance increases, power decreases and viceversa
For Bulb A:
P = V2R ⇒ RA = V2P = 220260 = 806
For Bulb B:
P = V2R ⇒ RB = V2P = 2202100 = 484
So, RB < RA
⇒ PB > PA
⇒ Bulb B will glow brightly