Question

Two bulbs A and B contain $16$g $O_2$ and $16$g $O_3$ respectively. Which of the statements are true?

• A. Both bulbs contain same number of atoms.
• B. Both bulbs contain different number of atoms.
• C. Both bulbs contain same number of molecules.
• D. Bulb A contains $N_A/2$ molecules while bulb B contains $N_A/3$ molecules. $(N_A=$ Avogadro's number).

Answer 1

Answer: (A), (D)

The correct options are
A Both bulbs contain same number of atoms.
D Bulb A contains $N_A/2$ molecules while bulb B contains $N_A/3$ molecules. $(N_A=$ Avogadro's number).

Number of $O$ atoms in $O_2=\frac{16}{32}\times 2\times N_A=1\times N_A$
Number of $O$ atoms in $O_3=\frac{16}{48}\times 3\times N_A=1\times N_A$
Number of $O_2$ atoms in bulb $A$ $=\frac{16}{32}\times N_A=\frac{1}{2}{N}_A$
Number of $O_3$ atoms in bulb $B$ $=\frac{16}{48}\times N_A=\frac{1}{3}{N}_A$
Hence, options A & D are correct.