Question

Two bulbs A and B contains 16 g $O_2$ and 16g $O_3$, respectively. Which of the statements are true?

• A. $\text{Both bulbs contain same number of atoms.}$
• B. $\text{Both bulbs contain different number of atoms.}$
• C. $\text{Both bulbs contain same number of molecucles.}$
• D. $\text{Bulb A contains}\frac{N_A}{2}\text{molecules while bulb B contains}\frac{N_A}{3}\text{molecules.}(N_A=\text{Avogadro's number)}$.

Answer 1

Answer: (A), (D)

The correct options are
A $\text{Both bulbs contain same number of atoms.}$
D $\text{Bulb A contains}\frac{N_A}{2}\text{molecules while bulb B contains}\frac{N_A}{3}\text{molecules.}(N_A=\text{Avogadro's number)}$.

a. Number of of $O_2$ atoms $=\frac{16}{32}\times 2\times N_A=1\times N_A$

Number of of $O_3$ atoms $=\frac{16}{48}\times 3N_A=1\times N_A$

so both bulbs contain same number of atoms.

d. Number of of $O_2$ molecules $=\frac{16}{32}{N}_A=\frac{1}{2}{N}_A$

Number of of $O_3$ molecules $=\frac{16}{48}\times N_A=\frac{1}{3}{N}_A$
so, (a) and (d) are correct