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Gas laws from KTG

Two bulbs A...

Question

Two bulbs $A$ and $B$ of equal capacity are filled with $H e$ and $S O_{2}$ respectively at the same temperature. If the pressure in two the bulbs is same, what will be the ratio of $r m s$ speed of the molecules of two gases?

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Solution

For $H e$ : $u_{r m s} = \sqrt{[(3 R T) / M]}$

$= \sqrt{[(3 R T) / 4]}$
For $S O_{2} : u_{r m s} = \sqrt{[(3 R T) / M]}$

$= \sqrt{[(3 R T) / 64]}$
$\frac{u_{r m s} o f H e}{u_{r m s} o f S O_{2}} = 4$

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