Two bulbs are marked as ‘A’ having rating 60W, 220V & ‘B’ having rating 100W, 220V. They are connected in parallel to a 220 V source. Which of the two will glow brighter?
Bulb B.
When voltage is constant then P = V2R
P ∝ 1R so when R increases, power decreases and vice versa.
Bulb A: P = V2R ⇒ RA = V2P = 220260=806 Ω
Bulb B: P = V2R ⇒ RB = V2P = 2202100=484 Ω
So, RB < RA
⇒ PB > PA
⇒ Bulb B will glow brighter.