Two bulbs have ratings 100 W, 220 V and 60 W, 220 V respectively. Which one has a greater resistance?

Open in App

Solution

Given

For Bulb A:

power = 100W

voltage = 220V

We know that,

P = V² / R

R = V² / P

= ( 220)² / 100

= 484 ohms..

For Bulb B:

power = 60W

Voltage = 220V

R = V² / P

= (220 )² / 60

= 2420 / 6

= 806.66 ohm...

Therefore, the bulb B has greater resistance.

Suggest Corrections

Similar questions

Q. Two bulbs have ratings 100 W, 220V and 60 W, 220V. Which one has the greater resistance?

Q. Out of the following bulbs rated 40W, 220V ,60W, 220V and 100W, 220V which one will glow the brightest when connected in series to a supply of 220V ?

Q. Two bulbs are rated

60 W, 220 V

and

240 W, 220 V

respectively. The ratio of their ratio of their resistances is

Two bulbs are marked as ‘A’ having rating 60W, 220V & ‘B’ having rating 100W, 220V. They are connected in parallel to a 220 V source. Which of the two will glow brighter?

Q. Two electric bulbs have ratings respectively of

25 W, 220 V

and

100 W, 220 V

. If the bulbs are connected in series with a supply of

440 V

, which bulb will fuse?

Join BYJU'S Learning Program

Two bulbs have ratings 100 W, 220 V and 60 W, 220 V respectively. Which one has a greater resistance?

Given For Bulb A: power = 100W voltage = 220V We know that, P = V² / R R = V² / P = ( 220)² / 100 = 484 ohms.. For Bulb B: power = 60W Voltage = 220V R = V² / P = (220 )² / 60 = 2420 / 6 = 806.66 ohm... Therefore, the bulb B has greater resistance.

Given

For Bulb A:

power = 100W

voltage = 220V

We know that,

P = V² / R

R = V² / P

= ( 220)² / 100

= 484 ohms..

For Bulb B:

power = 60W

Voltage = 220V

R = V² / P

= (220 )² / 60

= 2420 / 6

= 806.66 ohm...

Therefore, the bulb B has greater resistance.