Two bulbs have ratings 100 W, 220V and 60 W, 220V. Which one has the greater resistance?

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Solution

$P = \frac{V^{2}}{R}$
where P is power in Watt(W)
R is resistance in ohm
V is voltage in volts(V)
So, Power is directly proportional to the Resistance if Voltage is same.

Now compare
100W, 220V and 60W,220V
Voltage is same.
So, lower the power higher will be the resistance.
Thus, 60W,220V will have greater resistance.

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Two bulbs have ratings 100 W, 220V and 60 W, 220V. Which one has the greater resistance?

P=V2Rwhere P is power in Watt(W) R is resistance in ohmV is voltage in volts(V)So, Power is directly proportional to the Resistance if Voltage is same.Now compare100W, 220V and 60W,220VVoltage is same.So, lower the power higher will be the resistance.Thus, 60W,220V will have greater resistance.