Two bulbs marked 200 W, 250 V and 100 W, 250 V are joined in series to a 250 V supply. Power consumed in the circuit is

33.33 W

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66.67 W

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100 W

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50 W

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Solution

The correct option is B
66.67 W

We know that, power, P = $\frac{V^{2}}{R}$

R = $\frac{V^{2}}{P}$

For first bulb, R = $\frac{250^{2}}{200}$ = 312.5 $Ω$

For second bulb, R = $\frac{250^{2}}{100}$ = 625 $Ω$

When connected in series, total resistance, R = 312.5 + 625 = 937.5 $Ω$

So power consumed = $\frac{V^{2}}{R}$ = $\frac{250^{2}}{937.5}$ = 66.67 W

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Two bulbs marked 200 W, 250 V and 100 W, 250 V are joined in series to a 250 V supply. Power consumed in the circuit is

The correct option is B 66.67 W We know that, power, P = V2R R = V2P For first bulb, R = 2502200 = 312.5 Ω For second bulb, R = 2502100 = 625 Ω When connected in series, total resistance, R = 312.5 + 625 = 937.5 Ω So power consumed = V2R = 2502937.5 = 66.67 W