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Question

Two bulbs, one of 200W and the other of 100W, are connected in series with a 100V battery which has no internal resistance. Then,
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A
the current passing through the 200W bulb is more than that through the 100W bulb
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B
the power dissipation in the 200W bulb is more than that in the 100W bulb
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C
the voltage drop across the 200W bulbs is more than that across the 100W bulb
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D
the power dissipation in the 100W bulb is more than that in the 200W bulb
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Solution

The correct option is D the power dissipation in the 100W bulb is more than that in the 200W bulb
Bulbs are connected in series and resistance of 100 W is greater then that of 200 watt.
In series, P=I2R (Here I is constant)
So, PR
So, power of 100 W will be greater in the combination.

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