Two buses are moving in opposite directions at 90 kmph and 135 kmph. Their lengths are 1.65 km and 1.35 km respectively. The time taken by the slower bus to cross the faster bus in seconds is:

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Solution

The correct option is E
48

Let distance covered by slower train be 'x'

$\frac{x}{90}$ = $\frac{3 - x}{135}$

x = 1.2 km

Time taken = $\frac{1200 \times 3600}{90 \times 1000}$ = 48 secs

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Two buses are moving in opposite directions at 90 kmph and 135 kmph. Their lengths are 1.65 km and 1.35 km respectively. The time taken by the slower bus to cross the faster bus in seconds is:

The correct option is E 48 Let distance covered by slower train be 'x' x90 = 3−x135 x = 1.2 km Time taken = 1200×360090×1000 = 48 secs

The correct option is E
48

Let distance covered by slower train be 'x'

$\frac{x}{90}$ = $\frac{3 - x}{135}$

x = 1.2 km

Time taken = $\frac{1200 \times 3600}{90 \times 1000}$ = 48 secs