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Standard XII

Mathematics

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Two buses sta...

Question

Two buses start from a bus terminal with a speed of $20$ km/hr at interval of $10$ minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at interval of $8$ minutes?

3

km/hr

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4

km/hr

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5

km/hr

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7

km/hr

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Solution

The correct option is C $5$ km/hr
Let speed of the man be $x$ km/hr.
Distance covered in $10$ minutes at $20$ km/hr $=$ Distance covered in $8$ minutes at $(20 + x)$ km/hr.
$\Rightarrow 20 \times \frac{10}{60} = (20 + x) \times \frac{8}{60}$
$\Rightarrow 200 = 160 + 8 x$
$\Rightarrow 8 x = 40$
Hence, speed of the man $= 5$ km/hr.

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Two buses start from a bus terminal with a speed of 20 km/hr at interval of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at interval of 8 minutes?

The correct option is C 5 km/hrLet speed of the man be x km/hr. Distance covered in 10 minutes at 20 km/hr = Distance covered in 8 minutes at (20+x) km/hr. ⇒20×1060=(20+x)×860 ⇒200=160+8x ⇒8x=40 Hence, speed of the man =5 km/hr.

Two buses start from a bus terminal with a speed of $20$ km/hr at interval of $10$ minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at interval of $8$ minutes?