Question

Two cannons shoots cannonballs simultaneously as shown in the figure. The mass and speed of the the cannonball at ground level is half that of the cannonball at height H. Each cannonball is in air for more than two seconds.

The cannonball projected from ground remains in air for a time T. Find the horizontal distance covered by the projectile.

• A. $\frac{1}{2}{v}_{0}T$
• B. $v_{0}T$
• C. $\frac{1}{2}{v}_{0}T\sin \theta$
• D. $\frac{1}{2}{v}_{0}T\cos \theta$
• E. $v_{0}T\cos \theta$

Answer 1

The correct option is D $\frac{1}{2}{v}_{0}T\cos \theta$

Horizontal component of speed of cannon shot on ground=$\frac{v_0}{2}cos\theta$

Time for which the projectile remains in air=$T$

Thus total horizontal distance covered by projectile=$\frac{1}{2}{v}_{0}Tcos\theta$

Hence correct answer is option D.