Question

Two capacitor $C_1$ and $C_2$ of capacity $6\mu F$ and $3\mu F$ respectively are charged to 100V and 50V separately and connected as shown in the figure. Now all the switches $S_1,S_2$ and $S_3$ are closed.

Suppose $q_1,q_2$ and $q_3$ be the magnitude of charges flown from switches $S_1,S_2$ and $S_3$ after they are closed. Then,

• A. $q_1=q_{3}and{q}_2=0$
• B. $q_1=q_3=\frac{q_2}{2}=100\mu C$
• C. $q_1=q_3=2q_2=100\mu C$
• D. $q_1=q_2=q_3=100\mu C$

Answer 1

The correct option is D $q_1=q_2=q_3=100\mu C$


Let $q\left(\mu C\right)$ of charge flows from the battery. Then charges on both the capacitors will increase by ‘q’

Applying Kirchoff’s law,
$200-\left(\frac{600+q}{6}\right)-\left(\frac{150+q}{3}\right)=0$
$q=100\mu C$
$\therefore$ charges on $6\mu F$ is $700\mu C$
charges on $3\mu F$ is $250\mu C$
Charge flown $=100\mu C$