Question

Two capacitors $6\mu F/200V$ and $1\mu F/60V$ are connected in series. The maximum emf which can be applied is:

• A. $260V$
• B. $200V$
• C. $70V$
• D. none of these

Answer 1

The correct option is C $70V$

As the capacitors are in series so the charge remains same.
The charge on small capacitance $\left(1\mu F\right)$, $Q_1=60\mu C$
Thus we can not apply charge which is greater than $Q_1=60\mu C$.
The potential on big capacitance $\left(6\mu F\right)$ for same charge $Q_1$ is $V_b=\frac{60}{6}=10V$
Thus the max emf $=60+10=70V$