Two capacitors each having capacitance C and breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will be

2 C and 2 V

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C/2 and V/2

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2 C and V/2

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C/2 and 2 V.

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Solution

The correct option is A C/2 and 2 V.

We know that the charge on a capacitor is
$\begin{matrix} Q = C V C \propto \frac{1}{V} i n s e r i e s c o m b i n a t i o n C_{n e t} = \frac{C_{1} C_{2}}{C_{1} + C_{2}} H e n c e, C_{e q} = \frac{C}{2} V_{c o m b i n a t i o n} = 2 V \end{matrix}$

$∴$ option $D$ is correct.

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Two capacitors each having capacitance C and breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will be

The correct option is A C/2 and 2 V.We know that the charge on a capacitor is Q=CVC∝1VinseriescombinationCnet=C1C2C1+C2Hence,Ceq=C2Vcombination=2V∴ option D is correct.