1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Two capacitors of capacitance 2μF and 4μF respectively are connected in series. The combination Is connected across a potential difference of 10 V. The ratio of energies stored by capacitors will be

A
1:2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2:1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1:4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B 2:1Given, G1=2μF,C2=4μF and V=10 volt Capacitors are connected in series1C=1C1+1C2∴C=4×24+2=d43The charge of combinationq=CV=43×10=403The enrgy of 2μF capacitor E=12×q2C1=12×16009×2=4009The energy of 4μF capacitor E2=12×q2C2=12×16009×4=2009The ratio of energies isE1E2=40092009=21

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Electrical Power in an AC Circuit
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program