You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Partially Filled Dielectrics

Two capacitor...

Question

Two capacitors of capacitance 2C and C are charged to potential difference 2V and V respectively. Now the charged capacitors are connected with a resistor R as shown in figure. Switch ‘S’ is closed at t = 0.

What is the total heat produced in circuit till steady state is obtained?

$\frac{1}{3} C V^{2}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{C V^{2}}{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{2}{3} C V^{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{3}{5} C V^{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$\frac{1}{3} C V^{2}$

Heat developed in circuit is

$H = U - U_{F} = \frac{1}{2} (2 C) (2 V)^{2} + \frac{1}{2} C V^{2} - [\frac{1}{2} (3 C) (\frac{5 V}{3})^{2}] = \frac{1}{3} C V^{2}$

Suggest Corrections

Similar questions

Two capacitors of capacitance 2C and C are charged to potential difference 2V and V respectively. Now the charged capacitors are connected with a resistor R as shown in figure. Switch ‘S’ is closed at t = 0.

What is the current in circuit as function of time?

Q. Three capacitors (of capacitances C, 2C and 3C) and three resistors (of resistance R, 2R and 3R) are connected with a battery and switch S as shown in the figure. When switch S is open, charges on the capacitors are shown. Switch S is closed at t =0 sec. The time constant of the circuit will be

Q. A Circuit contains a resistor of resistance

R

and a capacitor

C_{1}

of capacitance

C

, a second Capacitor

C_{2}

of capacitance

2 C

, and a battery that provides an emf of

V

, as shown above.
Initially, both switch 1 is closed, switch 2 is open and the circuit is at steady state. At time

t = 0

, both switch 1 is closed and switch 2 is closed. After the circuit reaches steady state, what is the charge

Q_{2}

on capacitor

C_{2}

Q. A Circuit contains a resistor of resistance

R

and a capacitor

C_{1}

of capacitance

C

, a second Capacitor

C_{2}

of capacitance

2 C

, and a battery that provides an emf of

V

, as shown above. Initially both switches are open and both capacitors are uncharged. At time t=0, Both switches are closed. After the circuit reaches steady state, what is the charge

Q_{2}

on capacitor

C_{2}

Q. A capacitor of Capacitance

C

is charged to potential

V_{0}

and is connected in circuit as shown in the figure, Switch

S_{1}

is closed at

t = 0.

After time

t = \frac{π \sqrt{L C}}{6},

switch

S_{1}

is opened , while

S_{2}

is closed. If initially both the switches were open and capacitor of capacitance

2 C

was uncharged, the maximum charge stored on

2 C

would be

Join BYJU'S Learning Program

Two capacitors of capacitance 2C and C are charged to potential difference 2V and V respectively. Now the charged capacitors are connected with a resistor R as shown in figure. Switch ‘S’ is closed at t = 0. What is the total heat produced in circuit till steady state is obtained?

The correct option is A 13CV2 Heat developed in circuit is H=U–UF=12(2C)(2V)2+12CV2−[12(3C)(5V3)2]=13CV2

Two capacitors of capacitance 2C and C are charged to potential difference 2V and V respectively. Now the charged capacitors are connected with a resistor R as shown in figure. Switch ‘S’ is closed at t = 0.

What is the total heat produced in circuit till steady state is obtained?

The correct option is A
$\frac{1}{3} C V^{2}$

Heat developed in circuit is

$H = U - U_{F} = \frac{1}{2} (2 C) (2 V)^{2} + \frac{1}{2} C V^{2} - [\frac{1}{2} (3 C) (\frac{5 V}{3})^{2}] = \frac{1}{3} C V^{2}$