Two capacitors of capacitance 4μF and 6μFare charged to potential of 30V and 20V respectively. If both are connected parallel with positive terminal of the second capacitor and negative terminal with positive terminal of the common potential is
A
25V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Zero
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
15V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
24V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is BZero As positive terminal of one capacitor is connected to negative terminal of second capacitor, common potential after connection is V=C1V1−C2V2C1+C2 V=[(4×30)−(6×20)]10−6(4+6)×10−6 V=0