Two capacitors of capacitances 20μF and 40μF are connected in parallel and the potential difference across them is 10V. The charge on the positive plate of 20μF is
A
400μC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
20μC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
200μC
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
40μC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C200μC Given the two capacitors are connected in parallel and the potential difference across them is 10V