Question

Two capacitors of capacitances $20\mu \text{F}$ and $40\mu \text{F}$ are connected in parallel and the potential difference across them is $10\text{V}$. The charge on the positive plate of $20\mu \text{F}$ is

• A. $400\mu \text{C}$
• B. $20\mu \text{C}$
• C. $200\mu \text{C}$
• D. $40\mu \text{C}$

Answer 1

The correct option is C $200\mu \text{C}$

Given the two capacitors are connected in parallel and the potential difference across them is $10\text{V}$

For the $20\mu \text{F}$ capacitor:

Using $Q=CV$, we get charge on it will be

$Q=20\mu \text{F}\times 10\text{V}=200\mu \text{C}$

Hence, option (c) is the correct answer.