Two capacitors of capacitances $3 μ F$ and $5 μ F$ respectively are joined in parallel and the combination is connected in series with a third capacitor of capacitance $2 μ F$ . Find the resultant capacitance.

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Solution

Effective combination in parallel $C_{P} = 3 + 5 = 8 μ F$
Effective combination in series $C_{s} = \frac{8 \times 2}{8 + 2}$
$= \frac{16}{10} = 1.6 μ F$

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