Two capillaries made of same material but of different radii are dipped in a liquid. The rise of liquid in one capillary is 2.2 cm and that in the other is 6.6 cm. The ratio of their radii is

9 : 1

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1 : 9

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3 : 1

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1 : 3

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Solution

The correct option is C
3 : 1

$r \propto \frac{1}{h} \Rightarrow \frac{r_{1}}{r_{2}} = \frac{h_{2}}{h_{1}} = \frac{6.6}{2.2} = \frac{3}{1}$

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Two capillaries made of same material but of different radii are dipped in a liquid. The rise of liquid in one capillary is 2.2 cm and that in the other is 6.6 cm. The ratio of their radii is

The correct option is C 3 : 1 r∝1h⇒r1r2=h2h1=6.62.2=31

The correct option is C
3 : 1

$r \propto \frac{1}{h} \Rightarrow \frac{r_{1}}{r_{2}} = \frac{h_{2}}{h_{1}} = \frac{6.6}{2.2} = \frac{3}{1}$