Two capillaries made of same material but of different radii are dipped in a liquid. The rise of liquid in one capillary is $2.2 c m$ and that in the other is $6.6 c m$ . The ratio of their radii is

9 : 1

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1 : 9

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3 : 1

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1 : 3

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Solution

The correct option is C $3 : 1$
As we know,
$r \propto \frac{1}{h} \Rightarrow \frac{r_{1}}{r_{2}} = \frac{h_{2}}{h_{1}} = \frac{6.6}{2.2} = \frac{3}{1}$ .

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The correct option is C $3 : 1$
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