Two capillary tubes $A$ and $B$ of diameter $1 m m$ and $2 m m$ respectively are dipped vertically in a liquid. If the capillary rise in $A$ is $6 c m$ , then the capillary rise in $B$ is

2 c m

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3 c m

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4 c m

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6 c m

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9 c m

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Solution

The correct option is A $3 c m$
Diameter of capillary tube, $A = 1 m m$
Diameters of capillary tube, $B = 2 m m$
and $h_{1} = 6 m$
We know that, $h_{1} r_{1} = h_{2} r_{2}$
$\Rightarrow 6 \times 1 = h_{2} \times 2$
$\Rightarrow$ Capilliary rise in tube $B$ ,
$h_{2} = \frac{6}{2} = 3 c m$ .

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Two capillary tubes A and B of diameter 1 mm and 2 mm respectively are dipped vertically in a liquid. If the capillary rise in A is 6 cm, then the capillary rise in B is

The correct option is A 3 cmDiameter of capillary tube, A=1 mmDiameters of capillary tube, B=2 mmand h1=6 mWe know that, h1r1=h2r2⇒6×1=h2×2⇒ Capilliary rise in tube B,h2=62=3 cm.

Two capillary tubes $A$ and $B$ of diameter $1 m m$ and $2 m m$ respectively are dipped vertically in a liquid. If the capillary rise in $A$ is $6 c m$ , then the capillary rise in $B$ is

The correct option is A $3 c m$
Diameter of capillary tube, $A = 1 m m$
Diameters of capillary tube, $B = 2 m m$
and $h_{1} = 6 m$
We know that, $h_{1} r_{1} = h_{2} r_{2}$
$\Rightarrow 6 \times 1 = h_{2} \times 2$
$\Rightarrow$ Capilliary rise in tube $B$ ,
$h_{2} = \frac{6}{2} = 3 c m$ .