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Standard XII

Physics

Archimedes' Principle

Two capillary...

Question

Two capillary tubes of same diameter are put vertically one each in two liquids whose relative densities are $0.8$ and $0.6$ and surface tensions are $60 a n d 50 d y n e / c m$ respectively. Ratio of heights of liquids in the two tubes $h_{1} / h_{2}$ is____

\frac{10}{9}

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\frac{3}{10}

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\frac{10}{3}

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\frac{9}{10}

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Solution

The correct option is D $\frac{9}{10}$
$h = \frac{2 T c o s θ}{ϱ g r}$
$h α \frac{T}{ϱ}$
So, $\frac{h_{1}}{h_{2}} = \frac{T_{1} \times ϱ_{2}}{ϱ_{1} \times T_{2}} = \frac{60 \times 0.6}{0.8 \times 50} = \frac{36}{40} = \frac{9}{10}$

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Similar questions

Two capillary tubes of same diameter are put vertically one each in two liquids whose relative densities are 0.8 and 0.6 and surface tensions are 60 and 50 dyne/cm respectively. Ratio of heights of liquids in the two tubes $\frac{h_{1}}{h_{2}}$ is

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Two capillary tubes of same diameter are put vertically one each in two liquids whose relative densities are 0.8 and 0.6 and surface tensions are 60 and 50dyne/cm respectively. Ratio of heights of liquids in the two tubes h1/h2 is____

The correct option is D 910h=2TcosθϱgrhαTϱSo, h1h2=T1×ϱ2ϱ1×T2=60×0.60.8×50=3640=910

Two capillary tubes of same diameter are put vertically one each in two liquids whose relative densities are $0.8$ and $0.6$ and surface tensions are $60 a n d 50 d y n e / c m$ respectively. Ratio of heights of liquids in the two tubes $h_{1} / h_{2}$ is____

The correct option is D $\frac{9}{10}$
$h = \frac{2 T c o s θ}{ϱ g r}$
$h α \frac{T}{ϱ}$
So, $\frac{h_{1}}{h_{2}} = \frac{T_{1} \times ϱ_{2}}{ϱ_{1} \times T_{2}} = \frac{60 \times 0.6}{0.8 \times 50} = \frac{36}{40} = \frac{9}{10}$