Two capillary tubes P and Q are dipped in water. The height of water level in capillary P is $\frac{2}{3}$ to the height in Q capillary. The ratio of their diameters is

2 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 : 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 : 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
3 : 2

$r \propto \frac{1}{h} \Rightarrow \frac{r_{P}}{r_{Q}} = \frac{h_{Q}}{h_{P}} = \frac{h}{\frac{2}{3} h} = \frac{3}{2}$

Suggest Corrections

Similar questions

Two capillary tubes P and Q are dipped in water. The height of water level in capillary P is 2/3 to the height in capillary Q. The ratio of their diameters is

Q. Two capillaries

P

and

Q

are dipped in water. The height of water level in capillary

P

2 / 3

to the height in

Q

capillary. The ratio of diameter is

Q. If two capillary tubes of radii

r_{1}

and

r_{2}

in the ratio

1 : 2

are dipped vertically in water, then the ratio of capillary rises in the respective tubes is

A capillary tube of length 10 cm is dipped 3 cm inside water. The water rises up to 5 cm in the capillary. If the same tube is dipped 6 cm inside water, the water will rise in capillary up to the height

Q. Two capillary tubes of different diameters are dipped in water. The rise of water is _________.

Join BYJU'S Learning Program

Two capillary tubes P and Q are dipped in water. The height of water level in capillary P is 23 to the height in Q capillary. The ratio of their diameters is

The correct option is B 3 : 2 r∝1h⇒rPrQ=hQhP=h23h=32

Two capillary tubes P and Q are dipped in water. The height of water level in capillary P is $\frac{2}{3}$ to the height in Q capillary. The ratio of their diameters is

The correct option is B
3 : 2

$r \propto \frac{1}{h} \Rightarrow \frac{r_{P}}{r_{Q}} = \frac{h_{Q}}{h_{P}} = \frac{h}{\frac{2}{3} h} = \frac{3}{2}$