Given: uA=10 m/s, uB= 12 m/s, a=2 m/s2, d=150 m
The distance travelled by car A , when it stops,
SA=u2A2a=1022×2=25 m
The distance travelled by car B , when it stops,
SA=u2B2a=1222×2=36 m
∴ Minimum distance between the cars when both are stop is 150−(25+36)=89 m
Hence, option B is correct.