wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two cars A and B are 5 km apart on a line joining South to North. Car A further North is streaming west at 10 km/hr and Car B is streaming North at 10 km/hr. What is their closest distance of approach?


A
5 km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
52 km
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2 km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3 km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 52 km
Velocity of car A, VA=10^j km/h
Velocity of car B, VB=10^i km/h
Velocity of car B w.r.t A, VBA=VBVA=10^i+10^j
Magnitude, VBA=102+102=102 km/h
tanθ=1010=1θ=45
Talking w.r.t A

For minimum distance,
Smin=AC=ABsin45°
=5(12)
=52 km

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Motion in 2D
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon