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Question

Two cars A and B are initially 100 m apart with A behind B. Car A starts from rest with a constant acceleration 2 m/s2 towards car B and at the same instant car B starts moving with constant velocity 10 m/s in the same direction. Time after which car A overtakes car B is:

A
14.36 s
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B
16.18 s
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C
10 s
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D
16.54 s
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Solution

The correct option is B 16.18 s
Distance traveled by car A=SA
Distance traveled by car B=SB
According to formula S=ut+12at2
SA=0t+12×2t2
SB=10t+12×0t2
Car A will overtake car B when
SA=SB+100
Putting the value SA and SB
+2=10t+100
+210t100=0
After solving for t, we get
t=16.18sec possible
t=6.10sec not possible
So option B is correct.

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