Question

# Two cars A and B are initially 100 m apart with A behind B. Car A starts from rest with a constant acceleration 2 m/s2 towards car B and at the same instant car B starts moving with constant velocity 10 m/s in the same direction. Time after which car A overtakes car B is:

A
14.36 s
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B
16.18 s
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C
10 s
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D
16.54 s
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Solution

## The correct option is B 16.18 sDistance traveled by car A=SADistance traveled by car B=SBAccording to formula S=ut+12at2SA=0t+12×2t2SB=10t+12×0t2Car A will overtake car B whenSA=SB+100Putting the value SA and SB+2=10t+100+2−10t−100=0After solving for t, we gett=16.18sec possiblet=−6.10sec not possibleSo option B is correct.

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