Two cars start at the same time from one point and move along two roads at right angles to each other Their speeds are 36 km/hr and 48 km/hr respectively After 15 seconds the distance between them will be

400 m

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150 m

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300 m

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250 m

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Solution

The correct option is C 250 m
Distance travelled by the 1st car in 15 seconds = OA = $(36 \times \frac{5}{18}) \times 15 m = 150 m$
Distance travelled by the 2nd car in 15 seconds = OB = $(48 \times \frac{5}{18}) \times 15 m = 200 m$
$∴$ Distance between them after 15 seconds = AB = $\sqrt{O A^{2} + O B^{2}} = \sqrt{150^{2} + 200^{2}}$
= $\sqrt{22500 + 40000} = \sqrt{62500} = 250 m$

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Two cars start at the same time from one point and move along two roads at right angles to each other Their speeds are 36 km/hr and 48 km/hr respectively After 15 seconds the distance between them will be

The correct option is C 250 mDistance travelled by the 1st car in 15 seconds = OA = (36×518)×15m=150mDistance travelled by the 2nd car in 15 seconds = OB = (48×518)×15m=200m∴ Distance between them after 15 seconds = AB = √OA2+OB2=√1502+2002= √22500+40000=√62500=250m