Question

Two cars start from rest and accelerate uniformly. Car A attains a velocity of 10 m/s in 4 s. Car B attains a velocity of 10 m/s in 5 s. The average velocity of car A in the first 4 s is the average velocity of car B in the first 5 s.

• A. equal to
• B. more than
• C. less than

Answer 1

The correct option is A equal to

For uniform acceleration,
Average velocity, $v_{avg}=\frac{v+u}{2}$

$v_{avg}$ of car A in the first 4 s = $\frac{v+u}{2}$
= $\frac{10+0}{2}$ = 5 m/s

$v_{avg}$ of car B in the first 5 s = $\frac{v+u}{2}$
= $\frac{10+0}{2}$ = 5 m/s

For both the cars, $v_{avg}$ = 5 m/s