Two cars started moving from a point. First car travels towards north and covers 40 km distance every hour & the other car moves towards East and covers 30 km every hour. Find the shortest distance between them after 2 hours in km.

Open in App

Solution

In two hours first car has travelled a distance of $2 \times 40 = 80 k m$ towards north and the second car would have travelled $2 \times 30 = 60 k m$ towards east.

The shortest distance between them can be calculated using Pythagoras theorem.

$A B^{2} = O A^{2} + O B^{2}$
$A B^{2} = (80)^{2} + (60)^{2} = 6400 + 3600 = 10000$
$A B = 100 k m$ .

Suggest Corrections

Similar questions

Two cars started moving from a point, one towards north at 40 km/hr & other towards East at 30 km/hr. The shortest distance between them after 2 hours in km is ___

Two cars started moving from a point, one toward north at 30 km/hr & other toward East at 40 km/hr : distance b/w them after 2 hr is ___

The distance between two milestones is 230 km and two cars start simultaneously from the milestones and start moving towards each other.. The distance between them after three hours is 20 km. If the speed of one car is less than that of other by 10 km/hr, find the speed of both the cars.

Q. The distance between two stations is 300 km. Two cars start simultaneously from these stations and move towards each other . The speed of one of them is 7 km/h more than that of the other. If the distance between them after 2 hours of their start is 34 km. Find the speed of each car.

Q. The speed of a car is increased by

2

km after every hour. If the distance traveled in the first hour was

35

km, what was the total distance traveled in

12

hours ?

Join BYJU'S Learning Program

Two cars started moving from a point. First car travels towards north and covers 40 km distance every hour & the other car moves towards East and covers 30 km every hour. Find the shortest distance between them after 2 hours in km.

In two hours first car has travelled a distance of 2×40=80 km towards north and the second car would have travelled 2×30=60 km towards east. The shortest distance between them can be calculated using Pythagoras theorem. AB2=OA2+OB2 AB2=(80)2+(60)2=6400+3600=10000 AB=100 km.