wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two cars started moving with initial velocities u and 2u. For the same deceleration, their respective stopping distances are in the ratio

A
1:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1:2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1:4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
4:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1:4
For the first car:

v12=u2−2asFor first car${ v }_{ 1 }^{ 2 }={ u }^{ 2 }-2as$
Initial velocity = u
Final velocity = 0
Deceleration = a
Using the equation of motion: v2=u22aS
0=u2aS1
S1=u2a

For the second car:
Initial velocity = 2u
Final velocity = 0
Deceleration = a
Using the equation of motion: v2=u22aS
0=(2u)22aS2
S2=2ua

S1S2=u2a2ua
S1S2=14=1:4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equations of Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon