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Question

Two cars started moving with initial velocities u and 2u. For the same deceleration, their respective stopping distances are in the ratio

A
1:1
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B
1:2
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C
1:4
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D
2:1
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E
4:1
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Solution

The correct option is C 1:4
For the first car:

v12=u2−2asFor first car${ v }_{ 1 }^{ 2 }={ u }^{ 2 }-2as$
Initial velocity = u
Final velocity = 0
Deceleration = a
Using the equation of motion: v2=u22aS
0=u2aS1
S1=u2a

For the second car:
Initial velocity = 2u
Final velocity = 0
Deceleration = a
Using the equation of motion: v2=u22aS
0=(2u)22aS2
S2=2ua

S1S2=u2a2ua
S1S2=14=1:4

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